Function to Replace Substring within a String:
Return to List
' with NumberToReplace as Optional Last Parameter
Public Function ReplaceWithin(ByVal strString As String, _
ByVal strFind As String, _
ByVal strReplace As String, _
Optional ByVal NumberToReplace As Integer) As String
' Purpose: To replace all occurrences of one string in another
Dim intPos As Integer
Dim intLP As Integer
Dim intLen As Integer
Dim strTemp As String
Dim intCount As Integer
intCount = 0
' find each search string and replace with target intLen = Len(strFind)
intPos = InStr(strString, strFind)
While intPos <> 0
If NumberToReplace > 0 And NumberToReplace = intCount Then
GoTo LOOP_ESCAPE
End If
strTemp = strTemp & Left$(strString, intPos - 1)
strTemp = strTemp & strReplace
strString = Right$(strString, Len(strString) - intPos - intLen + 1)
intPos = InStr(strString, strFind)
intCount = intCount + 1
Wend
' append remainder upon failure of last InStr search LOOP_ESCAPE:
strTemp = strTemp & strString
ReplaceWithin = strTemp
End Function